x^2-(x+4)(x-4)=

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Solution for x^2-(x+4)(x-4)= equation: 


Simplifying
x2 + -1(x + 4)(x + -4) = 0

Reorder the terms:
x2 + -1(4 + x)(x + -4) = 0

Reorder the terms:
x2 + -1(4 + x)(-4 + x) = 0

Multiply (4 + x) * (-4 + x)
x2 + -1(4(-4 + x) + x(-4 + x)) = 0
x2 + -1((-4 * 4 + x * 4) + x(-4 + x)) = 0
x2 + -1((-16 + 4x) + x(-4 + x)) = 0
x2 + -1(-16 + 4x + (-4 * x + x * x)) = 0
x2 + -1(-16 + 4x + (-4x + x2)) = 0

Combine like terms: 4x + -4x = 0
x2 + -1(-16 + 0 + x2) = 0
x2 + -1(-16 + x2) = 0
x2 + (-16 * -1 + x2 * -1) = 0
x2 + (16 + -1x2) = 0

Reorder the terms:
16 + x2 + -1x2 = 0

Combine like terms: x2 + -1x2 = 0
16 + 0 = 0
16 = 0

Solving
16 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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